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[Kernel] Handle timeout errors properly
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parent
5e0c4b76ac
commit
74b06da6b2
2 changed files with 8 additions and 2 deletions
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@ -45,10 +45,13 @@ bool Kernel::signalEvent(Handle handle) {
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switch (t.status) {
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case ThreadStatus::WaitSync1:
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t.status = ThreadStatus::Ready;
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t.gprs[0] = SVCResult::Success; // The thread did not timeout, so write success to r0
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break;
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case ThreadStatus::WaitSyncAny:
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t.status = ThreadStatus::Ready;
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t.gprs[0] = SVCResult::Success; // The thread did not timeout, so write success to r0
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// Get the index of the event in the object's waitlist, write it to r1
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for (size_t i = 0; i < t.waitList.size(); i++) {
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if (t.waitList[i] == handle) {
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@ -151,7 +154,7 @@ void Kernel::waitSynchronization1() {
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return;
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}
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regs[0] = SVCResult::Success;
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regs[0] = SVCResult::Timeout; // This will be overwritten with success if we don't timeout
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auto& t = threads[currentThreadIndex];
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t.waitList.resize(1);
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@ -236,7 +239,7 @@ void Kernel::waitSynchronizationN() {
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return;
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}
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regs[0] = SVCResult::Success; // If the thread times out, this should be adjusted to SVCResult::Timeout
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regs[0] = SVCResult::Timeout; // This will be overwritten with success if we don't timeout
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// If the thread wakes up without timeout, this will be adjusted to the index of the handle that woke us up
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regs[1] = 0xFFFFFFFF;
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t.waitList.resize(handleCount);
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@ -262,10 +262,13 @@ int Kernel::wakeupOneThread(u64 waitlist, Handle handle) {
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switch (t.status) {
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case ThreadStatus::WaitSync1:
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t.status = ThreadStatus::Ready;
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t.gprs[0] = SVCResult::Success; // The thread did not timeout, so write success to r0
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break;
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case ThreadStatus::WaitSyncAny:
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t.status = ThreadStatus::Ready;
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t.gprs[0] = SVCResult::Success; // The thread did not timeout, so write success to r0
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// Get the index of the event in the object's waitlist, write it to r1
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for (size_t i = 0; i < t.waitList.size(); i++) {
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if (t.waitList[i] == handle) {
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